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домен 2cos(3x)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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преобразование Лапласа 2sin(x2 )−3x

Solution

44s²+1 −3s²

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Определение диапазона функций

Набор значений зависимой переменной, для которой определена функция

Перепишите как

xx²−6x+8 =y

Умножьте обе части на x²−6x+8

x=y(x²−6x+8)

Диапазон - это набор значений y, для которых дискриминант больше или равен нулю

Дискриминант x=y(x²−6x+8): 4y²+12y+1

4y²+12y+1≥ 0 : y≤ −√2−32 or y≥ √2−32

Проверьте, включены ли конечные точки интервала диапазона

y=−√2−32 : Включен

y=√2−32 : Включен

Поэтому диапазон равен

f(x)≤ −√2−32 or f(x)≥ √2−32

Solve instead

обратный Лаплас 2sin(x2 )−3x

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

домен 2cos(3x)

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