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domain of 2cos(3x)

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∫ 2cos(3x)dx

Solution

23 sin(3x)+C

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∫ 2cos(3x)dx

Извлечь константу: ∫a·f(x)dx=a·∫f(x)dx

=2· ∫ cos(3x)dx

Применить подстановку интеграла: ∫ cos(u)13 du

=2· ∫ cos(u)13 du

Извлечь константу: ∫a·f(x)dx=a·∫f(x)dx

=2· 13 · ∫ cos(u)du

Использовать общий интеграл: ∫ cos(u)du=sin(u)

=2· 13 sin(u)

Делаем обратную замену u=3x

=2· 13 sin(3x)

Упростите 2· 13 sin(3x): 23 sin(3x)

=23 sin(3x)

Добавить константу к решению

=23 sin(3x)+C

Fractions Add, Subtract Like Denominators Examples

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

domain of 2cos(3x)

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