f(x)=2x+3, g(x)=-x^2+5, (f\circ g)(2)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for partial fractions long division line

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начальная точка (−9, 4), (−132 , 6)

Solution

(−232 , 2)

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Solution steps

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Начальная точка с учетом середины (x₁, y₁) и конечная точка (x₂, y₂): (2x₁−x₂, 2y₁−y₂)

(x₁, y₁)=(−9, 4), (x₂, y₂)=(−132 , 6)

=(2(−9)−(−132 ), 2· 4−6)

После упрощения получаем

=(−232 , 2)

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

f(x)=2x+3, g(x)=-x^2+5, (f\circ g)(2)

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