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prove (tan^2(x)-1)/(sec^2(x))=(tan(x)-cot(x))/(tan(x)+cot(x))

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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преобразование Лапласа cos(3t)

Solution

ss²+9

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L{cos(3t)}

Используйте таблицу Преобразования Лапласа: L{cos(at)}=ss²+a²

L{cos(3t)}=ss²+3²

=ss²+3²

=ss²+9

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обратный Лаплас cos(3t)

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

prove (tan^2(x)-1)/(sec^2(x))=(tan(x)-cot(x))/(tan(x)+cot(x))

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