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перехваты 3x-10

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for expand factor rationalize

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домен 2+log₂(4+x)

Solution

x>−4

Interval Notation

(−4, ∞ )

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Solution steps

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Определение диапазона функций

Набор значений зависимой переменной, для которой определена функция

Диапазон базовой функции cos равен −1≤ cos(3x)≤ 1

−1≤ cos(3x)≤ 1

Умножьте края диапазона на: 2

−2≤ 2cos(3x)≤ 2

Поэтому диапазон равен

−2≤ f(x)≤ 2

Solve instead

диапазон 2+log₂(4+x)

обратная 2+log₂(4+x)

перехваты 2+log₂(4+x)

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

перехваты 3x-10

Solution

Solution steps

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