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обратный Лаплас 4x2+x+94x2−9
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Solution
δ(t)−118e−3t2+138e3t2
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Solution steps
Solve by:
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L−1{4x2+x+94x2−9}
Извлечь элементарную дробь из 4x2+x+94x2−9:1−114(2x+3)+134(2x−3)
=L−1{1−114(2x+3)+134(2x−3)}
Используйте свойство линейности обратного преобразования Лапласа Для Функций f(s),g(s) и констант a,b:L−1{a·f(s)+b·g(s)}=a·L−1{f(s)}+b·L−1{g(s)}