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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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Ron had one dollar. Jane had 2 dollars. how much would they have together?

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

π

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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среднее квадратичное −4, 5, 6, 9

Solution

6.28490…

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Среднее Квадратичное

Для набора данных, содержащего значения a₁, … , a_n (n элементов)
среднеквадратичное (среднее квадратическое) - это x_rms=√x₁²+x₂²+…+x_n²n

Вычислить сумму квадратов членов набора данных: x₁²+x₂²+…+x_n²=158

Вычислите количество слагаемых в наборе данных: n=4

Вычислите √x₁²+x₂²+…+x_n²n : 6.28490…

=6.28490…

Addition/Subtraction Word Problems Examples

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