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(4^2)/(4^{-2)}

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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x²+y²=1

Solution

(a, b)=(0, 0), r=1

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Solution steps

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x²+y²=1

Уравнение окружности

(x−a)²+(y−b)²=r² представляет собой уравнение окружности с радиусом r, расположеном в центре точки (a, b)

Перепишите x²+y²=1 в виде стандартного уравнения окружности

(x−0)²+(y−0)²=1²

Следовательно, свойства окружности:

(a, b)=(0, 0), r=1

Quotient Exponent Rule Examples

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Notebook

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

(4^2)/(4^{-2)}

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