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(x-1-i)(x+1-i)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

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∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for expand factor rationalize

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simplify (x−1−i)(x+1−i)

Solution

(x²−2)−2xi

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Solution steps

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(x−1−i)(x+1−i)

Rewrite x−1−i in standard complex form: (x−1)−i

Rewrite x+1−i in standard complex form: (x+1)−i

=((x−1)−i)((x+1)−i)

Apply complex arithmetic rule: (a+bi)(c+di)=(ac−bd)+(ad+bc)i

=((x−1)(x+1)−(−1)(−1))+((x−1)(−1)−1· (x+1))i

Simplify ((x−1)(x+1)−(−1)(−1))+((x−1)(−1)−1· (x+1))i: (x²−2)−2xi

=(x²−2)−2xi

Solve instead

ddx ((x−1−i)(x+1−i))

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

(x-1-i)(x+1-i)

Solution

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